Question

two taps A and B together can fill a cistern in 25 minutes.if only the tap B is opened for last 10 minutes the cistern is filled in 30 minutes.fibd the time in which the tap A alone can fill it​

Answer 1

Answer:

Solution



Verified by Toppr

Part of the cistern filled by (A+B) in one minute =(201+251)=1005+4=1009

∴ Part of the cistern filled by (A+B) in 5 minutes =5×1009=209

Remaining part =1−209=2011

201 part of the cistern is filled by A in a minute

∴2011 part of the cistern is filled by A in 20×2011 minutes =11 minutes

∴  Total time taken to fill the cistern =(11+5)=16 min