Two taps can fill a cistern in 15 hours and 20 hours respectively .A third pipe can empty it in 30 hours. How long will it take to fill the cistern if all the taps are opened.
Answers
Answered by
10
check attachment for this
simple method id take lcm
and find efficiecny of each
and then solve
i have add all efficiency and then divide the lcm by adding all the efficiency
Attachments:
BhumikaT:
sorry but this time wrong answer
the correct answer is 12hrs
But thank u v.v.v much for rest of the answers
sorry ..let me check again
https://youtu.be/GW8ChELwWmE please check this video for yours basic doubts
ohhh sorry instead of subtracting i add 30 in the question....i will post you answer wait plz
okk
instead of adding all
do this
60/ (4+3-2)
60/5 = 12 hours....rest is same method
we have to only minus (-2) b/c third pipe emptying the cictern.....thnx now it is done
do this
60/ (4+3-2)
60/5 = 12 hours....rest is same method
we have to only minus (-2) b/c third pipe emptying the cictern.....thnx now it is done
Answered by
39
Answer:
Step-by-step explanation:
Tab 1 = 15 hours in 1 hours = 1/15
Tab 2 = 20 hours in 1 hours = 1/20
Tab 3 = 30 hours in 1 hours = 1/30
If all are open = 1/15+1/20-1/30
= 4+3-2/60
= 5/60
Total time = 1/5/60 = 60/5 = 12 hours
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