Two taps can fill a tank in 10 hours and 12 hours
respectively. An outlet pipe takes 60 hours to
empty the tank. If the two taps and the outlet
pipe are all opened together, how long will it
take for the tank to be filled?
Answers
Answered by
3
Step-by-step explanation:
Let two filling pipes be A and B, draining pipe is C.
Given that pipe A can fill a tank in 10 hours
=> In one hour it fills 1/10th part of the tank ( by cross multiplication method)
And pipe B can fill a tank in 12 hours
=> In one hour it fills 1/12th part of the tank.
And also given pipe C empties the tank in 20 hours => in one hour it empties 1/20th part.
If all three pipes operate simultaneously work done by both pipes A and B in one hour will be added and C work is subtracted.
Therefore work done by three pipes in one hour = 1/10 + 1/12 -1/20 = 8/60
In 1 hour 8/60th part of a tank can be filled.
Then complete tank can be filled in 60/8 = 7.5hrs
Answered by
0
Answer:
Answer is 6 hours I hope it is help full to you
Similar questions