Math, asked by ravicadiox1910, 1 year ago

two taps can fill a tank in 30 minutes and 40 minutes respectively.anodher tap can empty it in 24 minutes.if the tank is empty and all the three taps are kept open,in how much time the tank will be filled?

Answers

Answered by rituarya25nov
13

Answer:

Step-by-step explanation:

Time taken to fill the tank= 1/30

Time taken to fill tank by tap 2= 1/40

Time taken to empty tank = 1/24

so, 1/30+1/40 - 1/24

     = 4/240 = 1/60

therefore, 60 min is taken to fill the tank

Answered by aakarshdubey852
0

Answer:

Time taken to fill the tank will be 60 minutes

As one tap fill the tank in 30 minutes so time taken will be 1/30 minutes

Another tap fill the tank in 45 minutes so time taken will be 1/45 minutes

but, one tap or cistern can empty the tank in 24 minutes so, time taken to empty tank will be

1/24. minutes

As, these taps kept open so time taken to tank be filled is = 1/45 + 1/30. - 1/24

= 60 minutes

Hope it's helpful

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