Two taps can fill a tank in 6 hours and 8 hours respectively.
Answers
Answer:
Tap A can fill a tank in 6 hours. Tap B can fill a tank in 8 hours. ∴ The approximate time in which the tank will be half-filled = 2.36 ≈ 2.4 hours.
Answer:
From the information, in 1 hour;
Tap A, running alone, would fill 1/10 of the tank.
Tap B, running alone, would fill 1/15 of the tank.
Running together, both taps would fill
1/10+1/15= 1/6 of the tank in 1 hour I.e it would take 6 hours to fill the tank with both taps
running.
If Tap A alone runs for 8 hours it would fill 1/10 x 8 hours = 4/5 of the tank.
This means both taps had already filled 1/5 when they were running together.
Since 1/6 of the tank is filled per hour when both tanks are running, how much time would both take to fill 1/5 of the tank. DIVIDE
=1/5 ÷ 1/6
=1.2 hours =1 hour 12 minutes
Both taps were running for that time before tap B was closed.