Question

two taps can fill the tank in 16 hrs and 10 hrs respectively. The tank can be emptied by third tap in 12 hrs. In how much
time the tank will be emptied completely if all three taps are on?​

Answer 1

Answer:

one tap can do it in ten hrs

Answer 2

Step-by-step explanation:

let time in which tank can be emtied be x.

in 16 hrs 1 part can be filled by 1st tap

so in 1hr 1/16 part of tank can be filled.

in x hrs x/16 part of tank can be filled.

in 10 hrs 1 part can be filled by 2nd tap

so in 1hr 1/10 part can be filled by 2nd tap.

in x hrs x/10 part can be filled .

in 12 hrs 1 part can be emptied by 3rd tap.

so in 1 hr 1/12 part can be emptied.

in x hrs x/12 part can be emptied.

so the eqn becomes

x/16+x/10-x/12=1 part

$\frac{15x + 24x - 20x}{240} = 1 \\ 19x = 240 \\ x = \frac{240}{19}$