Question

Two taps M and N can fill a tank in 10 hours and 15 hours respectively.if the both taps are opened together the tank will be fill in?​

Answer 1

Answer:

Step-by-step explanation:

M=10,N=15

MN=(10+15)/2^2

MN=25/4

MN=6.2hrs

Answer 2

A n s w e r

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G i v e n

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• Tap M can fill the tank in 10 hours

• Tap N can fill the tank in 15 hours

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F i n d

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• Hours in which the tank is filled if both taps are opened

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S o l u t i o n

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• Let "h" be the hours in which the tank goes filled if both taps are opened

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$\underline{\bold{\texttt{One hour work of tap M :}}}$

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Tap M can fill the tank in 10 hours

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➜ $\sf \dfrac { 1 } { 10 }$

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$\underline{\bold{\texttt{One hour work of tap N :}}}$

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Tap N can fill the tank in 15 hours

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➜ $\sf \dfrac { 1 } { 15 }$

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$\underline{\bold{\texttt{One hour work when both taps are opened :}}}$

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➜ $\sf \dfrac { 1 } { 10 } + \dfrac { 1 } { 15 }$

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➜ $\sf \dfrac { 3 + 2 } { 30 }$

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➜ $\sf \dfrac { 5 } { 30 }$

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➜ $\sf \dfrac { 1 } { 6 }$

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$\underline{\bold{\texttt{"h" hour work when both taps are opened }}}$

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➜ $\sf \dfrac { 1 } { 6 } \times h$

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As we assumed that both taps can fill the tank if opened for "h" hours

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So,

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➜ $\sf \dfrac { 1 } { 6 } \times h = 1$

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➨ h = 6

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• Hence in 6 hours the tank can be filled if both taps are opened