Math, asked by akumarsingh1405, 11 months ago

two taps running together can fill a bath in 4 minutes which is filled by one of the tabs by itself in 7 minutes how long would it take if the other pipe is running by itself

Answers

Answered by shreya08012005
61

Step-by-step explanation:

tank filled by both tap in 4 minute= 1

tank filled by both tap in one minute= 1/4

tank filled by one tap in 7 minute= 1

tank filled by one tap in 1 minute = 1/7

let tank filled by other tank in 1 minute be x

1/7 +x = 1/4

x = 1/4 - 1/7

x = 7/28 - 4/28

x = 3/28

tank filled by other tap in one minute = 3/28

3/28 tank is filled by tap in =1 min

1 tank is filled by tap in = 28/3. min

Answered by mamiparida94
15

Step-by-step explanation:

tank filled by both tap in 1 min=1/4.

tank filled by one tap in 1 min = 1/7.

tank filled by another tap in one min=

1/4-1/7=3/28.

there fore,tank filled by another tap(1÷3/28)=28/3.

HOPE ITS HELPS U.

PLS MARK AS BRAINLIST...

...

Similar questions