two taps running together can fill a bath in 4 minutes which is filled by one of the tabs by itself in 7 minutes how long would it take if the other pipe is running by itself
Answers
Answered by
61
Step-by-step explanation:
tank filled by both tap in 4 minute= 1
tank filled by both tap in one minute= 1/4
tank filled by one tap in 7 minute= 1
tank filled by one tap in 1 minute = 1/7
let tank filled by other tank in 1 minute be x
1/7 +x = 1/4
x = 1/4 - 1/7
x = 7/28 - 4/28
x = 3/28
tank filled by other tap in one minute = 3/28
3/28 tank is filled by tap in =1 min
1 tank is filled by tap in = 28/3. min
Answered by
15
Step-by-step explanation:
tank filled by both tap in 1 min=1/4.
tank filled by one tap in 1 min = 1/7.
tank filled by another tap in one min=
1/4-1/7=3/28.
there fore,tank filled by another tap(1÷3/28)=28/3.
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