two taps running together can fill a tank 31 / 13 hours if one tap takes 3 hours more than the other to fill the tank in how much time will teach time take to fill the tank
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Let one tap fill the tank in x hrs.
Therefore, other tap fills the tank in (x + 3) hrs.
Work done by both the taps in one hour is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x2 + 3x)
13x2 – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 (rejecting the negative value)
Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.
Therefore, other tap fills the tank in (x + 3) hrs.
Work done by both the taps in one hour is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x2 + 3x)
13x2 – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 (rejecting the negative value)
Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.
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