Question

Two taps running together can fill a tank in 2 hours 40 minutes. If one tap takes 4 hours more than the other to fill a tank, then how much time will each tap take to fill the tank?

Answer 1

Answer:

let x be the time req by tap 1

then time req by tap 2 = x + 4

let V be the volume of tank.

Volume rate of tap 1 = V/x = v1

Volume rate of tap 2 = V/(x+4) = v2

2 hrs 40 mins = 2.66667 hrs.

(v1 + v2) × (2.66667) = V

1/x + 1/(x+4) = 3/8

(x+8)/x(x+4) = 3/8

8x + 64 = 3x^2 + 12x

3x^2 + 4x - 64 = 0

Solving we get,

x = 4

So, time taken by tap1 and tap2 is 4hrs and 8hrs respectively