Question

two taps running together can fill a tank in 3 hours.if on tank take 3 hours more than the other to fill a tank then find the time taken by them
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Answer 1

Answer:

Let one tap fill the tank in x hrs.

Therefore, other tap fills the tank in (x + 3) hrs.

Work done by both the taps in one hour is

1/x + 1/(x+3) = 13/40

(2x + 3)40 = 13(x2 + 3x)

13x2 – 41x – 120 = 0

(13x + 24)(x – 5) = 0

x = 5 (rejecting the negative value)

Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.