Two taps running together can fill the tank in 3 1/13 hours. If one tap takes 3 more hours than the other to fill the tank,then how much time will each tap take to fill the tank
Answers
Answer:
5
Step-by-step explanation:
Let one tap fill the tank in x hrs.
Therefore, other tap fills the tank in (x + 3) hrs.
Work done by both the taps in one hour is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x2 + 3x)
13x2 – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 (rejecting the negative value)
Hence, one tap takes 5 hrs and another 8 hrs separately to fill the tank.
MARK BRAINLIEST WILL YOU
Answer:
Tap 1 takes 5 hrs and Tap 2 takes 8 hrs to fill the tank.
Step-by-step explanation:
Let Tap 1 take x hrs to fill the tank
Tap 2 takes x+3 hrs
In 1 hour Tap 1 fills 1/x of the tank and tap 2 fills 1/(x+3) of the tank
3 1/13 = 40/13
1/x + 1/(x+3) = 13/40
2x + 3/ x² + 3x = 13/40
13(x² + 3x) = 40(2x+3)
13x² + 39x = 80x + 120
13x² - 41x -120 = 0
b² - 4ac = (-41)² - 4× -120 × 13
= 1681 + 6240
√b²-4ac = √7921 = 89
x = -b ± √b² - 4ac/ 2a
= 41 + 89/2a (x being time we take the positive value)
= 130/26 hrs
x = 5hrs
∴Tap 1 takes 5 hrs and Tap 2 takes 8 hrs to fill the tank
PLEASE MARK AS BRAINLIEST