two taps together can fill a tank completely in 3 1/13 min. the smaller tap takes 3 min more than the bigger tap to fill the tank.how much time does each tap take to fill the tank completely
Answers
Answered by
192
Answer:
5and 8 mins
Step-by-step explanation:
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Answered by
116
Answer:
One tap 5 minutes and another 8 minutes
Step-by-step explanation:
Given that two tap can fill a tank in 3 1/13 minutes = 13/40 (converting into proper fraction). So in 1 minute both the taps can fill 13/40th of the tank.
Therefore we assume that,
One tap can fill the tank in x minutes [in 1 minute 1/x] and the other in (x+3) minutes [in 1 minute 1/(x+3)] respectively,
Work done by the taps in 1 minute is
1/x + 1/(x+3) = 13/40
(2x + 3)40 = 13(x² + 3x)
80x + 120 = 13x² + 39x
13x²+39x -80x -120 =0
13x² – 41x – 120 = 0
(13x + 24)(x – 5) = 0
x = 5 ( ignoring the negative value)
Hence, one tap takes 5 minutes to fill the tank and another 8 minutes to fill the tank separately.
ketan3468:
hii
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