Math, asked by Rahatshaikh, 1 year ago

two taps together can fill a tank completely in 3 1/13 min. the smaller tap takes 3 min more than the bigger tap to fill the tank.how much time does each tap take to fill the tank completely ​

Answers

Answered by anujabaldota
192

Answer:

5and 8 mins

Step-by-step explanation:

Hope the attached image helps

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Answered by Anonymous
116

Answer:

One tap 5 minutes and another 8 minutes

Step-by-step explanation:

Given that two tap can fill a tank in 3 1/13 minutes = 13/40 (converting into proper fraction). So in 1 minute both the taps can fill 13/40th of the tank.

Therefore we assume that,

One tap can fill the tank in x minutes [in 1 minute 1/x] and the other in (x+3) minutes [in 1 minute 1/(x+3)] respectively,

Work done by the taps in 1 minute is

1/x + 1/(x+3) = 13/40

(2x + 3)40 = 13(x² + 3x)

80x + 120 = 13x² + 39x

13x²+39x -80x -120 =0

13x² – 41x – 120 = 0

(13x + 24)(x – 5) = 0

x = 5 ( ignoring the negative value)

Hence, one tap takes 5 minutes to fill the tank and another 8 minutes to fill the tank separately.


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