Question

two taps together fill a tank in 6 hours one of the tap alone fills it in 10 hours how long will it take to fill the tank if only the second tap is open​

Answer 1

Answer:

It's takes 15 hours

Step-by-step explanation:

Let A is the first tap and B is the other.

∵ the taps A and B fill the 1 tank in 6 hours.

∴ In 1 hour they fill 1/6 part of the tank.

Hence, A + B = 1/6 - - - - (1)

∵ tap A fills 1 part of tank in 10 hours

∴ In 1 hour it will fill 1/10 part of the tank.

Hence, A = 1/10 - - - - (2)

Form equation (1) and equation (2),

$A + B - A = \frac{1}{6} - \frac{1}{10}$

$B = \frac{5 - 3}{30}$

$B = \frac{2}{30}$

$B = \frac{1}{15}$

Hence, the tap B fills the 1/15 part of the tank in 1 hour.

∵ Tap B fills the 1/15 part of the tank in 1 hour

$∴ It \: will \: fill \: 1 \: part \: in \: \frac{ \frac{1}{1} }{15} = 15 \: hour$

Hence, on opening the second tap it takes 15 hours to fill the tank.