Question

Two teams are pulling a heavy chest, located at point X. The teams are 4.6 meters away from each other. Team A is 2.4 meters away from the chest, and Team B is 3.2 meters away. Their ropes are attached at an angle of 110°.

Triangle A B X is shown. Angle A X B is 110 degrees. The length of X B is 3.2, the length of B A is 4.6, and the length of A X is 2.4.

Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Which equation can be used to solve for angle A?

StartFraction sine (uppercase A) Over 2.4 EndFraction = StartFraction sine (110 degrees) Over 4.6 EndFraction
StartFraction sine (uppercase A) Over 4.6 EndFraction = StartFraction sine (110 degrees) Over 2.4 EndFraction
StartFraction sine (uppercase A) Over 3.2 EndFraction = StartFraction sine (110 degrees) Over 4.6 EndFraction
StartFraction sine (uppercase A) Over 4.6 EndFraction = StartFraction sine (110 degrees) Over 3.2 EndFraction

Answer 1

Please repost the question properly. I think you were trying to program. Forgive me if I am wrong...