Question

Two teams are pulling a rope with equal and opposite forces each of 5 kn in a tug of war so that a condition of equilibrium exists. What will be the tensile force in the rope?

Answer 1

Answer:

Explanation:

Tensile strength would be 5kn. Suppose at one end of the rope is a box attached to it. On one side it is pulled by 5 kn. To maintain it in equilibrium the T should also be the equal force but on opposite direction for that block that is T=F=5kn.

Hence for the rope tensile force would be 5 kn.