Two terms of an arithmetic sequence having natural number terms are 50 and Also, 60 is not a term of this
sequence. Is 134 a term of this sequence? Justify your opinion 5
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Given : t
5
=22 and t
15
=62
We know, t
n
=a+(n−1)d
So, t
5
=a+(5−1)d⇒a+4d=22 ....(I)
And, t
15
=a+(15−1)d⇒a+14d=62 ....(II)
Subtract eq.(I) from eq. (II), we get
⇒10d=40
⇒d=4
Hence, a=6
So, t
100
=6+(100−1)4
∴t
100
=402
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