Two the find HCF of numbers emperimently by equlid division lemma?
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lets take a=42
b=9
according to euclids division lemma
a=bq+r
42=9×4+6
9=6×1+3
6=3×2+0
so hcf of 42 and 9=3
lets a=49
b=7
according to the euclid division lemma
a=bq+r
49=7×7+0
so hcf of 7 and 49 = 7
b=9
according to euclids division lemma
a=bq+r
42=9×4+6
9=6×1+3
6=3×2+0
so hcf of 42 and 9=3
lets a=49
b=7
according to the euclid division lemma
a=bq+r
49=7×7+0
so hcf of 7 and 49 = 7
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