Two thin convex lenses of focal lenght 15cm and 30cm are placed in contact what will be power of the combination?
Answers
Answered by
66
f1 = 15cm, f2 = 30cm
Focal length of combination,
1/f=1/f1+1/f2
1/f= 1/15+1/30
1/f= (15+30)/(15*30)
f = 450/45
f= 10cm
Focal length of combination,
1/f=1/f1+1/f2
1/f= 1/15+1/30
1/f= (15+30)/(15*30)
f = 450/45
f= 10cm
Answered by
33
1m =100 cm
so, 0.15m and 0.30m
now, p=1/f
=1/0.15
=20/3 D ........1
now , p=1/0.30
=10/3 D........2
adding 1 & 2
=30/3 D
=10 D
ANS = 10 D [D STANDS FOR DIOPTRE SI UNIT OF POWER]
so, 0.15m and 0.30m
now, p=1/f
=1/0.15
=20/3 D ........1
now , p=1/0.30
=10/3 D........2
adding 1 & 2
=30/3 D
=10 D
ANS = 10 D [D STANDS FOR DIOPTRE SI UNIT OF POWER]
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