Two thin lenses are in contact and the focal length of the combination is 80 cm. If the focal length of one lens is 20 cm, then the power of the other lens will be(a) 1.66 D(b) 4.00 D(c) –100 D(d) –3.75 D
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P is the power of combination of two given, lens which power are P1 and P2
we know,
power =1/focal length
we know,
P = P1 + P2
1/feq = 1/f1 + 1/f2
1/80 =1/20 + 1/f2
1/f2 = 1/80 -1/20 = -3/80
f = -80/3 cm = -26.666 cm = -0.2666 metres
Calculate power by
1/f(in m)
1/-0.2666
Equals
-3.75D
Hence your answer is 'D'
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