Physics, asked by niharikhakhanna999, 4 months ago

Two thin rods OA and OB of equal length () and mass (m) are lying in xy plane as shown in the figure. The moment of inertia of the system about x-axis is
O:
O
m2
12
m2
3
m2
24
O
ma
B​

Answers

Answered by jitendrakumarpandey3
2

Answer:

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Answered by sourasghotekar123
0

Answer:

The correct answerwill be D Ix=Iy<Iz

Explanation:

From the above above question,

Two rods OA and OB of equal length and mass are lying on the xy plane as shown in figure.

Let Ix, Iy and Iz be the moment of inertia of the system about x, y and z axis respectively. Then,

Let OA=OB=l (in metres)

mA=mB=m kg

Moment of inertia of the system about x axis

Ix = 2(ml23sin245∘)

=ml23

(effective length of both rods is lsin45∘)

Moment of inertia of the system about y axis

Iy=2(ml23cos245∘)

=ml23

Moment of inertia of the system about z− axis

Iz=2(ml23)=2ml23

⇒Ix=Iy<Iz

Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

For more related question : brainly.in/question/18722533

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