Two thin rods of length each, and mass m and 2m are joined end to end to form a composite rod of length L. The composite rod is pivoted at the left end so that it can
rotate in the vertical plane, and then released from the horizontal position as shown. At the instant the rod becomes vertical, its kinetic energy is K and its angular velocity
is omega
omega is equal to:
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1
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Step-by-step explanation:
I want points
Answered by
1
Answer:
Find k by applying gain in k=loss in pe
Find i and apply K=1/2iw^2
p.s. use i=1/3mr^2 seperately for both the rods
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