Question

Two thin wood screens Aand Bare separated by 200 m .A bullet travelling horizontally at a speed of 600 m/s hits the screen A finally edges through B differences in the heights of holes is

Answer 1

here 
_____________________________________________
u = 600 m/s 

Time taken by bullet to cross 200 m 

200/ 600 = 1/3 sec

Difference in their heights =  gt²/2 = (10/9) /2 = 10/18 = 5/9 m 
_________________________________________________

Answer 2

Here,

U=600m/s

Time taken by the bullet to cross 200m=200/600=1/3

Differences in the height of holes=gt^2/2

=10×(1/3)^2/2

=10×(1/9)/2

=10/9×2

=10/18

=5/9m

I hope it will help for u ☺.