Question

two third of the first number is equal to the cube of the second number. if the second number is equal to 12% of 50,what is the sum of the first and second numbers?​

Answer 1

Step-by-step explanation:

second number = 50 × 12

------------------- = 6

100

2

---- × first number = 6 ^3

3

first number = 6^3 × 3

----------------= 324

2

required sum = 324 + 6= 330

answer = 330

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Answer 2

Given:

Let the first number be x and the second number be y

$\frac{2}{3}x=y\fra{3}{}....eq.1$

$y=\frac{12}{100} * 50....eq.2$

To find the sum of the first and second number

Solution:

From eq.2

$y=\frac{600}{100}$

$y=6$

Putting the value of y in eq.1, we get

$\frac{2}{3} x} \, =y{3}$

$\frac{2}{3} {x} =6^{3}$

$\frac{2}{3} {x} =216$

$2{x} =648$

${x} =324$

Then,

${x} + {y} =324+6$

${x} + {y} =330$

Hence,  the sum of the first and second numbers is 330.