two-thirds of a number is increased by 9, the sum will be 19 , find the number
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Let us take the no. be x.
2/3 of the no.=2x/3.
no. increased by 9 =2x/3+9.
ATQ,2x/3+9=19
or 2x/3=19-9
or 2x /3 =10
or 2x=10×3
or x=10×3/2
Therefore x =15.
Required number=15
2/3 of the no.=2x/3.
no. increased by 9 =2x/3+9.
ATQ,2x/3+9=19
or 2x/3=19-9
or 2x /3 =10
or 2x=10×3
or x=10×3/2
Therefore x =15.
Required number=15
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