Question

Two times a number decreased by 7 is 14 2q-7=14​

Answer 1

Answer:

Let the number be x.

Let the number be x.twice =2x

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x=

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x= 2

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x= 252

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x= 252

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x= 252

Let the number be x.twice =2xWhen it is decreased by 7 we get the following equation:2x−7=45⇒2x=45+7⇒2x=52⇒x= 252 ∴x=26

The number is 26.

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