Question

Two times the first number is equal to three times the second number. What is the ratio of the sum of the numbers and the difference of the numbers ?​

Answer 1

Answer:

Let the 3 numbers be a, b, and c. The given conditions are:

a=2b

c=3b

a+b+c=44×3 or 132

First, replace a and c in the third condition with their given values.

2b+b+3b=132

6b÷6=132÷6

b=22

Now that b is known, the values for a and c are quite easy to find.

a=2b, so a=44

c=3b, so c=66

Verify by getting their average.

44+22+66=132

132÷3=44

So the first number is 44.