Question

Two times the smallest of 3 consecutive odd intergers is 15 more than 3 times the greatest number.

Answer 1

2x = 3(x + 4) + 15

2x = 3x + 27

x= -27

Answer 2

The question should be => Three times the smallest of 3 consecutive odd intergers is 15 more than 3 times the greatest number.

If it would be two times the smallest, the equation would be wrong.

$\underline{\boxed{Answer}}$

Let the three consecutive odd integers be x, x + 2 and x + 4


Two times the smallest of 3 consecutive odd intergers is 15 more = 3x + 15


3 times the greatest number = 2(x + 4)



A/q,

3x + 15 = 2(x + 4)

3x + 15 = 2x + 8

3x - 2x = 15 - 8

x = 7



1st number => x => 7

2nd number => x + 2 => 7 + 2 => 9

3rd number => x + 4 => 7 + 4 => 11




$\therefore{}$ $\text{The numbers are 7, 9 and 11}$