two times the sum of some number plus is equal to times the difference of the
number and . Find the number.
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Let the digit be x and y
Given, the number of two digits is equal to six times the sum of its digits,
10x+y=6(x+y)
=>10x+y=6x+6y
=>4x=5y
=>x=
4
5
y
Now, when the digits are reversed, the number will be 10y+x
Let 10y+x=a(x+y)
=>10y+
4
5
y=a(
4
5
y+y)
=>
4
45
=a
4
9
=>a=5
Hence, if the digits are reversed the number so formed is equal to five times the sum of its digits.
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