Question

Two tiny spheres carrying charges of
1 muC and

3 muC are placed 8 cm apart in air. What is the coulomb
force on a unit positive test charge placed at the mid-point of the joining the two charges?​

Answer 1

that is calculated by coulombs law Firm=1/4π€o q1q2/r square

Explanation:

9×10 raised to power 9 ×1×3/8square

421875×10 raised to power 3.

Answer 2

Answer:

This is calculated by coulombs law :

This is calculated by coulombs law : Firm=1/4π€o q1q2/r square.

This is calculated by coulombs law : Firm=1/4π€o q1q2/r square.

This is calculated by coulombs law : Firm=1/4π€o q1q2/r square. 9×10 raised to power 9×1×3/8square

This is calculated by coulombs law : Firm=1/4π€o q1q2/r square. 9×10 raised to power 9×1×3/8square421875/10 raised to power 3.