Two tonnes of an iron ore containing 94% of Fe2O3 produces iron in pure state. Calculate the weight of iron.
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Answer:
1314 kg
Explanation:
94% of 2 tonnes comes out to be 1880 kg.
The molar mass of Fe2O3
= 2 * 55.8 (molar mass of iron) + 3 * 16 (molar mass of oxygen)
= 159.6
Percentage of iron by mass
= (2 * 55.8)/ 159.6
= (111.6)/ 159.6
Thus total mass of iron = 1880 * 111.6/159.6 = 1314 kg
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