Question

Two towers of height 28m and 36m are built at a distance of 15m . Find the distance between the tops of the tower

Answer 1

ED=BC=15m
CD=BE=28m

AB=AE-BE
AB=36m-28m
AB= 8m

$ac {}^{2} = ab {}^{2} + bc {}^{2} \ \ \\ ac {}^{2} = 8 {}^{2} + 15 {}^{2} \\ ac {}^{2} = 64 + 225 \\ ac {}^{2} = 289 \\ ac {}^{2} = 289 \\ ac {}^{2} = 17 {}^{2} \\ \sqrt{(ac) {}^{2} } = \sqrt{1(7 {)}^{2} } \\ ac = 17$
17m

Answer 2

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