Question

two towns A and B are 400 km apart Prakash and Jagdish started their cars from towns A and B respectively at the same time towards each other . When they were 10kilometers apart,the speed of prakash car exceeded the the speed of Jagdish car by 10km/hr , find their respective speeds.

plz explain the answer.
don't copy the answer
answer if you know correct answer
correct answer is 60km/hr and 70km/hr.
34km/hr and 44 km/hr is not correct answer.​

Answer 1

Answer:

Let the speed of Jagdish car be x km/hour.

The speed of prakash car exceeded the the speed of Jagdish car by 10km/hr

Speed of Prakash car be (x + 10) km/hour.

In 5 hours Jagdish and Prakash traveled 5x km and 5(x + 10) km respectively.

Total distance travelled by them = (400 - 10) km = 390 km.

$\sf 5x + 5(x + 10) = 3905x +5(x +10)=390$

$\sf 10x + 50 = 39010x +50=390$

$\sf 10x = 34010x =340$

$\sf x = 34x =34$

➦ Speed of Jagdish car = 34 km/hour.

➦ Speed of Prakash car = (34 + 10) km/hour = 44 km/hour.

$\therefore\textbf{Hence Speed of jagdish and Prakash car is 34 km/hr and 44 k /hr respectively}$

Answer 2

Answer:

400+10 kilometer/ 60+70/ 30×44

Step-by-step explanation:

i hope my answer is helpful