Two towns A and B are connected by a regular bus service with a bus leaving in either direction every T minutes. A man cycling with a speed of 20 km h–1 in the direction A to B notices that a bus goes past him every 18 min in the direction of his motion, and every 6 min in the opposite direction. What is the period T of the bus service and with what speed (assumed constant) do the buses ply on the road?
Answers
Answered by
5
Answer:
v=40km/h
Explanation:
Let the speed of each bus = v km/h
The distance between the nearest buses plying on either car = vT km...(i)
For buses going from town A to B:
Relative speed of bus in the direction of motion of man = (v - 20)
Buses plying in this direction go past the cyclist after every 18 min. Therefore, separation between the buses
= (v - 20)×(18/60)
From (i), (v - 20)×(18/60) = vT ...(ii)
For buses coming from B to A:
The relative velocity of bus with respect to man = (v + 20) Buses coming from town B past'the cyclist after every 6 min,
∴ (v + 20)×(6/60) = vT ...(iii)
Solving (ii) and (iii), we get\
v = 40 km/h and T = 2/30 h
Answered by
2
Answer:
20km/hr
Explanation:
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