Two train had started a journey from a station together to opposite directions. the speed of the first train is28km/h and the speed of the second train is 52km/h.How many time the distance between the two train is 480km/h.
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Given Train starts at the same time.
Hence, Time remains constant.
Speed of Train 'T1' be 'S1' = 40 km\hr
Speed of Train 'T2' be 'S2' = 45 km\hr
Let X be the distance at which trains meet.
Train T2 travels X + 40 km more than Train T1
According to the formula.
Speed = Distance / Time
Time1 = X + 40 / 45
Time2 = X / 40
From above two equations.
X + 40 / 45 = X / 40
45×X = 40×X+40×40
5×X = 1600
=320 km
Distance between two Stations = Distance at which train T1 meet + Distance at which Train T2 meet + Distance train T2 travels
= 320+320+40 = 680
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