Two train start simultaneously from two station 300km apart and move tpwards each other the speed of one train ismore than the other by 20 km/hr if
Answers
Answer:
280
Explanation:
300-20 is equals to 280 . That is why .
Let the points A and B denote the stations A and B respectively.
Let the first train start from station A and the second train start from station B at the same time and move towards each other.
Let the speed of the first train be x km/hr
∴ the speed of the other train =(x+20) km/hr
Distance travelled by first train in 2 hours =2x km
Distance travelled by second train in 2hours =2(x+20) km =(2x+40) km
Given, distance between two stations =300 km
A/q,we have
Distance travelled by first train +Distance travelled by second train +20=300
i.e., 2x+(2x+40)+20=300
4x+60=300
4x=300−60 [Transposing 60 to RHS]
4x=240
Thus, x= 240/4 =60
∴ Speed of the first train =60 km/hr and
speed of the second train =(60+20)krn/h =80 km/hr.