Question

Two trains 118m and 116m in length are running in opposite directions with velocities 40km hr and 30km hr respectively in what time will they completely pass each other

Answer 1

Hey mate here we go

*Step - by -Step*

$first \: we \: have \: to \: see \: the \: formula \\ time = \frac{distance \: or \: length \: of \: the \: train}{speed} \\ when \: two \: train \: travels \: in \: opposite \: direction \\ their \: length \: tak \: it \: as \: l1 \: and \: l2 \\ l1 = 118m \: \: l2 = 116m \\ speed \: of \: both \: train \\ s1 = 40 \frac{km}{hr} \: \: s2= 30 \frac{km}{hr} \\ lets \: take \: formula \: for \: caluculation \\ t = \frac{l1 + l2}{s1 + s2} \\ t = \frac{118 + 116}{40 + 30} \\ t = \frac{134}{70} \\t = 1.914 \frac{m}{ \frac{km}{hr} } \\ now \\ t = 1.914 \times \frac{3600}{1000 } \\ t = 6.89 \: secends \\ \: i \: hope \: this \: will \: help \: u \: very \: well \\ mark \: me \: as \: brainliest$