Question

two trains A and B leave Kolkata for Sikkim at 8:00 and 8:30 p.m. reactively and run at 90 km per hour and 120 km per hour respectively at what distance from Kolkata will the two trains meet​

Answer 1

Answer:

First calculate the distance travelled between 8:00-8:30 by train A= 90×30/60=45k.m.

we know that distance =time ×speed

so we take next time as x

then 90x+45=120x

120x-90x=45

30x=45

x=3/2or 1.5

so after 1hr30 min A and B meet