Question

Two trains A and B of length 400 m each are moving on two parallel tracks with auniform speed of 72 km h–1 in the same direction, with A ahead of B. The driver of B

decides to overtake A and accelerates by 1 m/s

past the driver of A, what was the original distance between them?


unnecessary answers will be reported ..​

Answer 1

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Answer 2

Explanation:

Given that,

uA=uB=72kmh−1=72×185=20ms−1

Using the relations, s=ut+21at2, we get

SB=uBt+21at2=20×50+21×1×(50)2

SB=1000+1250=2250m

Also, let SA be the distance covered by the train A, then SA=uA×t

     =20×50=1000m

Original distance between the two trains

= SB−SA

=2250−1000=1250m