Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?
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Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Relative speed = (60+ 90) km/hr = 150 km/hr
Converting it into m/s: = (150 x 5/18) m/s = 125/3 m/sTherefore, Required time = distance/speed = 2000 x 3/125 = 48 sec
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Answer:
The answer is 48 seconds.
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