Two trains are moving in the opposite directions at speed of 43 km/h and 51 km/h respectively. the time taken by the slower train to cross a man sitting in the faster train is 9 seconds. what is the length (in metres) of the slower train?
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hy
friend....
The speed of 1st train is 43km/h
Speed of 2nd train is 51km/h
When they meet at a common point
the total speed of slow train is = 43+51
= 94 km
To convert it in m/s we will multiple it by 5/18
= 94 x 5/18
= 26.11 m. per.sec
Now
Distance of slow train. =Speed× Time
= 26.11 x 9
= 234.99 m
thankyou
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Arun0:
You are assuming faster train length is zero.how could be possible..
When given is 43 and 51km/hr is speed of Train.. it is clearly seen that speed of slower train is 41. How could be 94
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