Two trains are moving in the same direction at 84.5 kmph and 48.5 kmph.The faster train crosses a man sitting in slower train in 15 seconds. The length of the faster train is ?
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Answered by
3
let length of faster train = L
length of slower train =M
now,
time = length /speed
time = L/relative velocity
15/3600 =L/(84.5-48.5)
1/240 = L/(36)
L =36/240 =9/60=3/20
=150m
length of fasted train =150 m
length of slower train =M
now,
time = length /speed
time = L/relative velocity
15/3600 =L/(84.5-48.5)
1/240 = L/(36)
L =36/240 =9/60=3/20
=150m
length of fasted train =150 m
BishalDas:
Many many thanks....
:-) my pleasure
Answered by
1
Let first train be x
Speed of x=84.5km/h change in SI unit
Speed of x=84.5km/h change in SI unit
sry glti ho gyi type krne me
no problem again type
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