two trains are moving in the same direction speed 65km/hr and 45km/hr.the faster train crosses the man in slower train by 18 sec
Answers
given,
fast train is 65km/hr
slow train is 45km/hr
time =18 sec
then,
The length of the faster train is
=(65 -45 )*(5/18)*18
=100 m
Given : two trains are moving in the same direction speed 65km/hr and 45km/hr.
the faster train crosses the man sitting in slower train by 18 sec
To Find : The length of the faster train
Solution:
the faster train crosses the man sitting in slower train
Hence distance covered by Faster train = Length of Faster Train + Distance covered by slower train
Distance covered by faster train = 65 * 18/3600
Distance covered by slower train = 45 * 18/3600
Length of Faster Train = x
=> 65 * 18/3600 = x + 45 * 18/3600
=> 20 * 18/ 3600 = x
=> 0.1 = x
Hence length of Faster train = 0.1 km = 100 m
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