Question

Two trains, can travel 15 km/hour faster than the other leave the same station at the same time , one travelling east and other west. at the end of 6 hours they are there are 570 km apart what is the speed of Train.​

Answer 1

Answer:

hey mate

Speed of slower train=x

Speed of faster train =x+15  

6(x+x+15)=570

so distance will be km.

divide by 6 and collect terms  

(2x+15)=95

subtract 15 from both sides

2x=80

divide by 2

x=40km/h (slower)

x+15=55 km/h (faster)  

6 hours

slower train 6×40=240 km

faster train 6×55=330

Total is sum= 570.

hope it helps: )

Step-by-step explanation:

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

• Two trains, can travel 15 km/hour faster than the other leave the same station at the same time , one travelling east and other west. at the end of 6 hours they are there are 570 km apart what is the speed of Train.

$\large\underline{ \underline{ \sf \maltese{ \: To \: Find :- }}}$

• Speed of both trains !

$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

• Let the speed of the slower train be$\sf\green{\: x\: km/hour}$
• Then the speed of the faster train will be$\sf\green{\:( x\:+\:15\:) km/hour}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\red{\boxed{ \sf \blue{ Both\: train\: travel\: in \:opposite\: direction\: for\:\sf\green{\: 6 \: hours} }}}$

The distance travelled by slower train = $\blue{\fbox\orange{6x\: km }}$

The distance travelled by Faster train = $\blue{\fbox\orange{6(x\:+15) km }}$

$\begin{gathered}\begin{gathered}\underline{\boldsymbol{According\:\: to\: \:the\:\: Question :}} \\\end{gathered}\end{gathered}$

$\quad {:} \longrightarrow \sf{\sf{6x \: + \: 6(x \: + \: 15) \: = \: 570 }}$

$\quad {:} \longrightarrow \sf{\sf{6x \: + \: 6x \: + \: 90 \: = \: 570}}$

$\qquad \quad {:}\longrightarrow\sf{\sf{12x \: + \: 90 \: = \: 570 }}$

$\qquad \quad {:}\longrightarrow\sf{\sf{12x \: </p><p> = \: 570\:-\:90 }}$

$\qquad \quad {:}\longrightarrow\sf{\sf{12x \: </p><p> = \: 480}}$

$\qquad \quad {:}\longrightarrow\sf{\sf{x \: </p><p> = \: \cancel \frac{480}{12} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{x \: = \: 40 }}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Speed \: of \: Slow \: Train \: = \underline {\underline{ 40km/h}}}\\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Speed \: of \: Fast \: Train \: = \underline {\underline{ 55km/h}}}\\\end{gathered}\end{gathered}$

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