Two trains, each 100 m long are moving in opposite directions. they cross each other in 8 seconds. if one is moving twice as fast the other, the speed of the faster train is
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Heya !
Total distance covered= 100 +100 = 200
Time-8 s
Let speed of slower train be V
Then speed of faster train will be 2V
Relative speed 2V+V = 3V
3V= 200/8 = 25m/s
V= 25/3 m/s
Speed of faster train = 50/3
M/s= 5×3
6/3= 5×12 = 60km/h
Hope this helps !
Total distance covered= 100 +100 = 200
Time-8 s
Let speed of slower train be V
Then speed of faster train will be 2V
Relative speed 2V+V = 3V
3V= 200/8 = 25m/s
V= 25/3 m/s
Speed of faster train = 50/3
M/s= 5×3
6/3= 5×12 = 60km/h
Hope this helps !
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