Question

Two, trains, each 100m long, moving in opposite
directions
,cross eachother in 8 seconds. If one is
moving twice as fast the other, then the speed of the
faster train is?​

Answer 1

Answer: 60 km/hr

Step-by-step explanation:

Let the speed of the slower train = x m/sec

Then the speed of the faster train = 2x m/sec

Relative speed = (x + 2x) m/sec = 3x m/sec

Therefore, (100 + 100)/8 = 3x

=> 24x = 200

=> x = 25/3

Speed of the faster train = 50/3 m/sec

= (50/3 × 18/5) km/hr

= 60 km/hr

քʟɛǟֆɛ ʍǟʀӄ ǟֆ ɮʀǟɨռʟɨɛֆȶ ǟռֆաɛʀ..

Answer 2

Let the speed of the slower train be x m/sec.

Let the speed of the slower train be x m/sec.Then, speed of the fater train = 2x m/sec.

Let the speed of the slower train be x m/sec.Then, speed of the fater train = 2x m/sec.Relative speed = (x + 2x) m/sec = 3x m/sec

∴

$\frac{100 + 100}{8 } = 3x$

$= > 24x = 200 \\ = >24x = 200 \\ = > x = \frac{25}{3} \\ so \: speed \: of \: the \: faster \: train \: = \frac{50}{3} m.sec \\ ( \frac{50}{3} \times \frac{18}{5} ) \frac{km}h \\ = 60 \frac{km}{hr}$