Question

two trains each of having a speed of 30km/h are headed at each other in opposite direction on the same track. A bird flies off one train to another with a constant speed of 60km/h when they are 60km apart till before they crash. Find the distance covered by the bird can make from one train to the other before they crash.

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Answer 1

Answer:

60 km

Explanation:

Answer :

Given, speed of each train = 30 km/h and

distance between them = 60km

As they are moving in opposite direction and same speed,

So they will crash at middle of the distance between them, i.e. 30km from each train.

Time taken to travel 30 km by each train = = 1h

Speed of the bird = 60 km and time = 1h

So distance traveled by bird in 1h = speed × time

= 60 × 1

= 60 km

As trains will come closer to each other, bird can make any number of trips because distance between trains will approach to 0.

So the time taken by bird will also tends to 0. Therefore, bird can make infinite number of trips.

Answer 2

➭ Question :-

$\longrightarrow$two trains each of having a speed of 30km/h are headed at each other in opposite direction on the same track. A bird flies off one train to another with a constant speed of 60km/h when they are 60km apart till before they crash. Find the distance covered by the bird can make from one train to the other before they crash.

➭ Given:-

$\longrightarrow$Speed of train: 30 km/hr

$\longrightarrow$Speed of bird : 60 km/hr

➭ To find :-

$\longrightarrow$Distance between two train

➭ Solution:-

As given that both the train are running on same speed which is 30 km/hr so both the train will expected to met or collide at 30 km and the time taken in this is :-

$\rm \longrightarrow \: t = \frac{distance \: travelled}{speed \: of \: the \: train} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm \longrightarrow t = \cancel \frac{30km}{30km/hr} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \rm \longrightarrow \boxed {t = 1hr} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

so, the birds that flying 60 km/hr will travel would be before the train colloid is

$\rm \longrightarrow \: d = time \: taken \times speed \: of \: bird \: \: \\ \rm \longrightarrow \: 1 \times 60 = 60km \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Hence, the distance between 2 trains is 60km