Question

Two trains leave a railway station at the same time. The first train travels due west and the second

due north. The first train travels 35 Km/h faster than the second train. If after two hours, they are

130 Km apart, find the average speed of each train​

Answer 1

Answer:

Let the average spped of the second train be x km/h.

Thus, the speed of the first train will be (x+5) km/h.

Distance travelled by the first train in two hours =2(x+5) km/h

Distance travelled by the second train in two hours =2x km/h

Using pythagoras theorem, we have

4x^2 +4(x+5) ^2

=50^2

4x^2+4x ^2

+40x+100=2500

8x^2+40x−2400=0

x ^2+5x−300=0

(x−15)(x+20)=0

x=15,−20

Ignore the negative value of the speed. We have,

Speed of the second train be 15 km/h.

Spped of the first train be (15+5)= 20 km/h.

Step-by-step explanation:

Hope it helps MRK ME AS BRAINLIEST