Two trains leave a railway station at the same time. The first train travels due west and the second
due north. The first train travels 35 Km/h faster than the second train. If after two hours, they are
130 Km apart, find the average speed of each train
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Answer:
Let the average spped of the second train be x km/h.
Thus, the speed of the first train will be (x+5) km/h.
Distance travelled by the first train in two hours =2(x+5) km/h
Distance travelled by the second train in two hours =2x km/h
Using pythagoras theorem, we have
4x^2 +4(x+5) ^2
=50^2
4x^2+4x ^2
+40x+100=2500
8x^2+40x−2400=0
x ^2+5x−300=0
(x−15)(x+20)=0
x=15,−20
Ignore the negative value of the speed. We have,
Speed of the second train be 15 km/h.
Spped of the first train be (15+5)= 20 km/h.
Step-by-step explanation:
Hope it helps MRK ME AS BRAINLIEST
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