Two trains leave lucknow at 6 : 00
a.M. And 6 : 30
a.M. Respectively. Speed of the first train is 60 km/hr while that of the second one is 70 km/hr. How many kilometers from lucknow will they meet
Answers
Answered by
0
They will meet at 210 km from lucknow.
First we have to assume some variables
Let time in which train train 2 meets train 1 = T
To cover the same distance as of train 2 , train 1 will take T+1/2 hours , because it has started 30 mins prior to train
Since distance covered by both are same
Therefore, 60(T+1/2)=70(T)
T=3 hours
Putting value of T in above equation as 70(T) we get 210KM.
Answered by
0
Given :
Speed of first train = 60km/hr
Speed of second train = 70km/hr
To find :
The distance at which they meet from lucknow
Solution :
- Time at which they meet = T
- Time required by first train = T+ 1/2
- we know that , Distance = Speed×Time
60(T+1/2) = 70T
60T + 30 = 70T
10T = 30
T = 3hrs
- Distance travelled by second train = 70T
= 70(3) = 210km
They will again meet at a distance of 210km from Lucknow
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