. two trains move in the same direction at 50 kmph and 32 kmph respectively. a man in the slower train observes the 15 seconds elapse before the faster train completely passes by him. what is the length of faster train
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Relative speed = 50 - 32 = 18 kmph
18 kmph = 18 × 5/18 = 5 m/s
time taken = 15 second
Length of faster train = rel. speed × time = 5 × 15 = 75m
18 kmph = 18 × 5/18 = 5 m/s
time taken = 15 second
Length of faster train = rel. speed × time = 5 × 15 = 75m
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Answer:
75mtrs
Step-by-step explanation:
speed is taken diff 50-32=18
convert 18kmph to m/sec=18*5/18=5mtrs/sec
s=d/t
5=d/15
d=75 mtrs
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